Saturday, 17 November 2007

Flowers

In a small town, there are three temples in a row and a well in front of each temple. A pilgrim came to the town with certain number of flowers.

Before entering the first temple, he washed all the flowers he had with the water of well. To his surprise, flowers doubled. He offered few flowers to the God in the first temple and moved to the second temple. Here also, before entering the temple he washed the remaining flowers with the water of well. And again his flowers doubled. He offered few flowers to the God in second temple and moved to the third temple. Here also, his flowers doubled after washing them with water. He offered few flowers to the God in third temple.

There were no flowers left when pilgrim came out of third temple and he offered same number of flowers to the God in all three temples. What is the minimum number of flowers the pilgrim had initially? How many flower did he offer to each God?

Level:Easy

3 comments:

Ananth said...

The answer is...... 2x + 3y = 38 and 9x + y = 71 where x is the no. of flowers he had initially and y is the no. of flowers he offered. I am answering in the form of equations just in case that someone doesn't want to know the answers.

Mayank Gupta said...

hi ananth , i got the same ans but by
one eqn : 8x = 7y. you see this gives u multiple ans and the lowest, which i think is what sajal(newton) wanted.
if there is one ans then i am as usual wrong.....

Ananth said...

Your answer is right, Mayank. I answered in the form of 2 equations just to conceal the answer just in case someone else wanted to have a try. They would have come to know the answer if I hadn't concealed it.